sort dictionary by value python

Using The sorted(dict1, key=dict1.get) Method.

The sorted() method is an in-built method in Python that is used to sort the elements of an iterable in a specific order (ascending or descending)

• In order to sort the dictionary using the values, we can use the power of the sorted() function.
• We can use the get() method and pass it to the key argument of the sorted() function.

			
					frameworks = {
  'VueJS': 2,
  'AngularJS': 4,
  'Ember': 5,
  'ReactJS': 1,
  'Svelte': 3
}

for each in sorted(frameworks, key=frameworks.get):
    print(each, frameworks[each])

			
	

			
	
			

		
	

Output

			
					ReactJS 1
VueJS 2
Svelte 3
AngularJS 4
Ember 5

			
	

			
	
			

		
	

• In order to sort the dictionary using its values in reverse order, we need to specify the reverse argument as true

			
					frameworks = {
  'VueJS': 2,
  'AngularJS': 4,
  'Ember': 5,
  'ReactJS': 1,
  'Svelte': 3
}

for each in sorted(frameworks, key=frameworks.get,reverse=True):
    print(each, frameworks[each])

			
	

			
	
			

		
	

Output

			
					Ember 5
AngularJS 4
Svelte 3
VueJS 2
ReactJS 1

			
	

			
	
			

		
	

python sort dictionary by value

Using OrderedDict (For Older Versions Of Python) Method

Dictionaries are generally unordered for versions before Python 3.7, so it is impossible to sort a dictionary directly. Therefore, to overcome this constraint, we need to use the OrderedDict subclass.

• An OrderedDict is a dictionary subclass that preserves the order in which key values are inserted in a dictionary.
• It is included in the collections module in Python.

			
					from collections import OrderedDict
frameworks = {
  'VueJS': 2,
  'AngularJS': 4,
  'Ember': 5,
  'ReactJS': 1,
  'Svelte': 3
}
a = OrderedDict(sorted(frameworks.items(), key=lambda x: x[1]))
for key,value in a.items():
  print(key, value)

			
	

			
	
			

		
	

Output

			
					('ReactJS', 1)
('VueJS', 2)
('Svelte', 3)
('AngularJS', 4)
('Ember', 5)